viernes, 24 de abril de 2015

[Q8] Genome rearrangements: double-cut-and-join distance

Let b and c be the number of breakpoints and cycles, respectively, as pointed by the breakpoint graph G for two genomes. Consider the next cases for the DCJ operation:
  1. Cutting two black lines belonging to different cycles and then joining
  2. Improper joining
  3. Proper joining with no successive lines
  4. Proper joining with successive lines in a cycle with two or more black lines
  5. Proper joining with successive lines in a 2-cycle
In which of the cases above, performing the DCJ operation would decrease c?
  1. Just in I and V
  2. Just in II, IV
  3. Just in I, III and V
  4. Just in II, III and IV
  5. None of the above.

Original idea by: Juan Felipe Hernández Albarracín.

viernes, 17 de abril de 2015

[Q7] Genome rearrangements: weighted median

For a given adjacency α to appear in the weighted median of n genomes, and assuming that all of them have the same weight, it is required for α to be present in:
  1. All genomes
  2. At least n - 1 genomes.
  3. At least the half of the genomes.
  4. At least one more genome than their conflicting adjacencies.
  5. None of the above.

Original idea by: Juan Felipe Hernández Albarracín.

viernes, 10 de abril de 2015

[Q6] Genome rearrangements: reversals

Given the fictitious genome G1.


Which of the following adjacencies sets represents the genome with the minimum reversal distance from G1?
  1. {ND5hND4t, ND4hND3t, ND3hCOIIIt, COIIIhCOIh}
  2. {ND5hND3t, ND3hCOIIIt, COIIIhND4h, ND4tCOIh}
  3. {ND5hND4t, ND4hCOIIIh, COIIItND3h, ND3tCOIh}
  4. {ND5hND4h, ND4tCOIIIh, COIIItND3h, ND3tCOIh}
  5. None of the above.

Original idea by: Juan Felipe Hernández Albarracín.

jueves, 2 de abril de 2015

[Q5] Phylogenetic trees: Parsimony

Given one rooted and one unrooted most parsimonious trees for the same group of species that consider only binary states, it is correct to say that:
  1. The edge where an hypothetical root for the unrooted tree is placed would affect the number of changes of state of this most parsimonious tree.
  2. Whether a tree is rooted or not, affects only in the possible positions of state changes for the most parsimonious tree.
  3. The rooted and unrooted tree will never be able to have the same topology.1
  4. Nothing can be concluded from this, since the interpretation of a rooted and an unrooted tree is different.
  5. None of the above.

1 Assuming that two trees could be considered to have the same topology if the only difference in them is the fact that a root is present or not.

Original idea by: Juan Felipe Hernández Albarracín.